![]() Regex aficionados like to use \x20, because it can’t be mistaken for any other character. By the way, \x20 is just another way to say space, as in the space you make with your space bar. Heres an example: // matches a number, some characters and another number const reg /d.d/ const str 'Java3foobar4Script' const newStr str.replace(reg, '-') console.log(newStr) // 'Java-Script'. This is the a\x20 branch of the negative lookahead. In JavaScript, regular expressions are also objects. Next we need to rule out opening a tags. Regular expressions are patterns used to match character combinations in strings.This is the /> branch of the negative lookahead, where simply means “a or p”. Let’s start by observing that the tag cannot be a closing a or p tag.To distinguish the tags we want to remove, we’ll do a negative lookahead right after the opening ]*>.We know that any tag we want to remove contains ]*>, that is, an opening.But the tricky part is matching only tags other than and the closing tag. replacement Can be a string or a function. So far this accounts for the first part of the regex, (?s-i)(?:]*>|(?!\A)\G)(?:(?!).)*?\K. Syntax js regexpSymbol.replace(str, replacement) Parameters str A String that is a target of the replacement.Specifically, the BSR is ]*>, which is an opening p tag, and the ESR is, the closing p tag.I won’t explain all the parts of this regex that are indebted to that you can just read his excellent explanation in the linked post. It’s modeled off of guy038’s now-famous replacing in a specific region of text regex.Since you’ve taken an interest, I’ll give a pretty detailed explanation of my regex.īy the way, I have a slight update that should work just as well, but is simpler: But how did you manage to find this solution? 3 Answers Sorted by: 176 You need to double escape any RegExp characters (once for the slash in the string and once for the regexp): 'TESTONE TESTONE'.replace ( new RegExp ('\\TESTONE','gm'),'foo') Otherwise, it looks for the end of the line and 'TESTONE' (which it never finds). I just used the find/replace form, with regular expressions on. Note If you replace a value, only the first instance will be replaced. The replace () method does not change the original string. The replace () method returns a new string with the value (s) replaced. ![]() Tough challenge! But I believe I have a regex that will meet your need.įIND: (?s-i)(?:]*>|(?!\A)\G)(?:(?!).)*?\K|a\x20 >))*>īut not said in Regex: Delete all html tags inside 2 other tags, except and : Description The replace () method searches a string for a value or a regular expression.
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